Can someone help me figure out this math problem?

A construction manager needs to order concrete for a sidewalk 45 feet by 5 feet. The concrete is to be 5 inches thick. How much concrete (in cubic yards, is needed)?





Can someone please tell me how I go about getting the answer to this problem?Can someone help me figure out this math problem?
first convert all the measurment into yards





3 feet = 1 yard so:





45 feet = 15 yards


5 feet = 1 2/3 = 5/3 yards





since there are 12 inches in a foot and three feet in a yard





36 inches = 1 yard so then





5 inches = 5/36 yards





now...to get the cubic yards you just need to multiply the length by the width by the hight (thickness) so





15 * 5/3 * 5/36 = 3 17/36 or 125/36 cubic yardsCan someone help me figure out this math problem?
first convert the distances to yards (ie from feet or inches to yards) and then multiply the figures. 3.472 cubic yards is the approximate answer
Volume = L x B x H





but you convert dimensions to yards (1 yard = 3 ft and 1ft = 12in)





Volume = 45/3 x 5/3 x 5/(3x12) = 3.47ft^3
First you need to get everything to common units. Let's go with feet. 45 ft x 5 ft x 5/12 ft to get the volume of area.





45 x 5 x 5/12 = 93.75 cubic feet


There are 27 cubic feet in a cubic yard ( 3 ft x 3 ft x 3ft )


93.75 cubic feet x 1 cubic yard / 27 cubic feet or


93.75/27 = 3.472 cubic yards